Question

The solutions of a quadratic equation are -5 and 2. Write in factored form, then standard form.

(x + 5)(x - 2) factored form

Answer 1

=
`x^2 + 3x - 10`

Explanation:

in factored form, find the equation where plugging x in will result in 0

plugging -5 or 2 into (x + 5)(x - 2) will result in 0

to change this from factored to standard form, FOIL

when you FOIL, (a + b)(c + d) = ac + ad + bc + bd

(x +5)(x - 2)

= (x * x) + (x * -2) + (5 * x) + (5 * -2)

=
`x^2 -2x + 5x - 10`

=
`x^2 + 3x - 10`

Answer 2

`(x + 5)(x - 2) \\ x(x - 2) + 5(x - 2) \\ {x}^(2) - 2x + 5x - 10 \\ = {x}^(2) + 3x - 10`