Question

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure

of the gas?
It decreases by a factor of four.
It increases by a factor of four.
It decreases by a factor of eight.
It increases by a factor of eight.

Answer 1

increases factor pressure by four

Step-by-step explanation:

Answer 2

It increases by a factor of four.

Step-by-step explanation:

To answer this question, we can use the pressure's law, which states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to the absolute temperature of the gas"

Mathematically:

`(p)/(T)=const.`

where

p is the pressure of the gas

T is its absolute temperature

The equation can be rewritten as

`(p_1)/(T_1)=(p_2)/(T_2)`

In this problem we have:

`T_2=4T_1`, since the absolute temperature of the gas is increased by 4 times

Here we want to find p2; solving for it, we find:

`p_2=(T_2)/(T_1)p_1 = (4T_1)/(T_1)p_1 = 4p_1`

So, the pressure

It increases by a factor of four.