Answer:
Explanation:
Please, share the answer options next time.
1) f(x) = 2x^2– x – 6 is a quadratic function.
2) The coefficients of this polynomial are a = 2, b = -1 and c = -6
2) Its graph opens up.
3) The x-value of the axis of symmetry and the vertex is x = -b / (2a), which here comes out to x = -(-1) / [2(2)], or x = 1/4
4) the y coordinate of the vertex is f(1/4), or -6 1/8
5) The vertex is at (1/4, -6 1/8)
6) The y-intercept is at f(0): 2(0)^2 - 0 - 6 = -6 => (0, -6)