What is the oxidation number of sulphur Cr2SO4

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23 votes

should be Chromium(III) sulfate: Cr₂(SO₄)₃

the oxidation number:

Cr₂(SO₄)₃ = 0

Cr = +3

SO₄ = -2

S + 4.O = -2

S + 4.-2 = -2

S = +6

Anton Strogonoff answered Dec 5, 2023

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