Question

A jar contains 44 4 4 red marbles, 44 4 4 green marbles, and 55 5 5 blue marbles. If we choose a marble, then another marble without putting the first one back in the jar, what is the probability that the first marble will be blue and the second will be green?

Answer 1

The probability of drawing a blue marble first and a green marble second without replacement is 0.14627.

Step-by-step explanation:

To find the probability that the first marble drawn is blue and the second marble is green, we need to calculate the probability of each event happening and then multiply them together. The probability of drawing a blue marble first is the number of blue marbles divided by the total number of marbles in the jar: 55/143. After removing the blue marble, there will be 54 blue marbles and a total of 142 marbles left in the jar. The probability of drawing a green marble second is then 54/142. To get the overall probability of both events happening, we multiply the two probabilities together: (55/143) * (54/142) = 2970/20314 = 0.14627 (rounded to 5 decimal places).