Question

The temperature of a gas is 100 K and its volume is 500.0 ml. If the volume increases to 1,000.0 ml,

what is the new temperature of the gas?

Answer 1

200k

Step-by-step explanation:

Answer 2

T₂ = 200 K

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Gas Laws

Charles' Law:
`\displaystyle (V_1)/(T_1) = (V_2)/(T_2)`

• V is volume
• T is temperature (in Kelvins)

Step-by-step explanation:

Step 1: Define

T₁ = 100 K

V₁ = 500.0 mL

V₂ = 1,000.0 mL

T₂ = ?

Step 2: Find T₂

1. Substitute [CL]:
   `\displaystyle (500.0 \ mL)/(100 \ K) = (1,000.0 \ mL)/(x \ K)`
2. Cross-multiply:
   `\displaystyle 500.0x \ mL \cdot K = 100000 \ mL \cdot K`
3. Isolate x:
   `x = 200 \ K`

Step 3: Check

We are given 1 sig fig as our lowest. Follow sig fig rules and round.

Since our final answer is in 1 sig fig, there is no need to round.