Answer:
D
Explanation:
-2×(x^-3) + 2e^(2x-2) = dy/dx
Integrate for y
y = -2×(x^-2)÷-2 + 2[e^(2x-2) ÷ 2] + c
y = 1/x² + e^(2x-2) + c
y is undefined only at x² = 0
Because x² is in the denominator
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