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. Suppose that a random sample of n = 102 children is selected from the population of newborn infants in Mexico. The probability that a child in this population weighs at most 2500 grams is presumed to be π = 0.15. Calculate the probability that thirteen or fewer of the infants weigh at m

User Flau
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1 Answer

7 votes

Answer:

30.85% probability that thirteen or fewer of the infants weigh at most 2500 grams

Explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:


E(X) = np

The standard deviation of the binomial distribution is:


√(V(X)) = √(np(1-p))

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that
\mu = E(X),
\sigma = √(V(X)).

In this problem, we have that:


n = 102, p = 0.15

So


\mu = E(X) = 102*0.15 = 15.3


\sigma = √(V(X)) = √(np(1-p)) = √(102*0.15*0.85) = 3.61

Calculate the probability that thirteen or fewer of the infants weigh at most 2500 grams

This is
P(X \leq 13), which using continuity correction is
P(X \leq 13 + 0.5) = P(X \leq 13.5), which is the pvalue of Z when X = 13.5.


Z = (X - \mu)/(\sigma)


Z = (13.5 - 15.3)/(3.61)


Z = -0.5


Z = -0.5 has a pvalue of 0.3085

30.85% probability that thirteen or fewer of the infants weigh at most 2500 grams

User Rosamunda
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