Question

Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if of chlorine were consumed?

Answer 1

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`273K=`

`n=(PV)/(RT)`

`n=(1atm* 3.16L)/(0.0820 L atm/K mol* 273K)=0.141moles`

`CH_4+4Cl_2\rightarrow 4HCl+CCl_4`

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces =
`(1)/(4)* 0.141=0.0352` moles of carbon tetrachloride

volume of carbon tetrachloride =
`moles* {\text {Molar volume}}=0.0352mol* 22.4L/mol=0.788L`

Thus volume of carbon tetrachloride that would be produced is 0.788 L