Question

Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, the concentrations of the different species are as follows. [NH3] = 0.105 M [N2] = 1.1 M [H2] = 1.50 M

Answer 1

The equilibrium constant is:

`k_c=0.0030M^(-2)`

Step-by-step explanation:

The correct equation is:

• N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

`k_c=([NH_3]^2)/([N_2]\cdot [H_2]^3)`

Substituting:

`k_c=((0.105M)^2)/((1.1M)\cdot (1.50M)^3)`

`k_c=0.0030M^(-2)`