Question

What is the molarity if 180g of MgSO4 is dissolved in a 500. mL volumetric flask?

Answer 1

Answer : The molarity of
`MgSO_4` in the solution is 2.99 M.

Explanation : Given,

Mass of
`MgSO_4` = 180 g

Volume of solution = 500.0 mL

Molar mass of
`MgSO_4` = 120.4 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of }MgSO_4* 1000}{\text{Molar mass of }MgSO_4* \text{Volume of solution (in mL)}}`

Now put all the given values in this formula, we get:

`\text{Molarity}=(180g* 1000)/(120.4g/mole* 500.0mL)=2.99mole/L=2.99M`

Therefore, the molarity of
`MgSO_4` in the solution is 2.99 M.