Question

When pent-1-ene is treated with mercury(II) acetate in methanol and the resulting product is reacted with NaBH4, what is the primary organic compound which results

Answer 1

please check the image and explanation:

Step-by-step explanation:

This whole process is known as oxymercuration and demercuration.

First step is mercuration and second step is demercuration.

it is an electrophilic addition reaction and generally we take water as a solvent but here methnaol is given so instead of attacking water , methanol will attack.

In this reaction first alkene reacts with mercuric acetate (AcO–Hg–OAc)

and it formed ring with alkene because pi electron of alkene share it with mercuric acetate and there is no formation of carbocation and hence there will not be any rearrangement possible.