Question

Given circle O, angle A has a measure of 36° and the radius is 10 cm, find the area of sector BOC.

Answer 1

The area of the sector BOC is A' = 31.4
`cm^(2)`

Explanation:

Radius of the circle = 10 cm = 0.1 m

Angle of sector
`\theta` = 36°

Area of the circle A =
`\pi r^(2)`

A = 3.14 ×
`0.1^(2)` = 0.0314
`m^(2)`

Now area of the sector BOC is

`A' = A ((\theta)/(360) )`

`A' = 0.0314 ((36)/(360) )`

A' = 0.00314
`m^(2)` = 31.4
`cm^(2)`

Therefore the area of the sector BOC is A' = 31.4
`cm^(2)`