Answer:
Explanation:
Area of 1st segment =128.9 sq.units Area of 2nd segment=91.6 sq.units
We know that the
area of segment is calculated [area of sector -area of triangle]
which is Area of segment=[(θ / 360°) × πr²- (1/2) r²sin θ]
(OR) r²[πθ/360° - sin θ/2], if 'θ' is in degrees ............(i)
Now as per the question θ =163 ° r=9 Putting the values in the equation(i)
Area of sector = 9²[Π *163/360 - (sin(163)/2)]
= 81[1.414 - (-0.355/2)] = 128.89
Now as per the question θ =120 ° r=11 Putting the values in the equation(i)
Area of sector = 11²[Π*120/360 - sin(120)/2]=121*[1.047-0.290] = 91.60
Therefore , Area of 1st segment is 128.9 sq.units
Area of 2nd segment is 91.60 sq.units ( to nearest tenth)