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\ce{2H2O2 -> 2H2O + O2}2HX

2




OX

2







2HX

2




O+OX

2





How many moles of \ce{H2O}HX

2




O will be produced from 26.0 \text{ g}26.0 g26, point, 0, start text, space, g, end text of \ce{H2O2}HX

2




OX

2




?

User Speerian
by
6.7k points

1 Answer

4 votes

Answer:

0.765 moles H₂O

Step-by-step explanation:

Based on the reaction:

2 H₂O₂ → 2 H₂O + O₂

2 moles of H₂O₂ produce 2 moles of H₂O

26g of H₂O₂ are:

26.0g H₂O₂ × (1mol / 34g) = 0.765 moles of H₂O₂.

Moles of H₂O are:

0.765 mol H₂O₂ × (2 mol H₂O / 2 mol H₂O₂) = 0.765 moles H₂O.

That means, 0.765 moles of H₂O are produced from 26.0g of H₂O₂

User Hein Zaw Htet
by
6.3k points