Question

Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 cm. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

Answer 1

Step-by-step explanation:

Given that,

Charge 1,
`q_1=-22\ \mu C`

Charge 2,
`q_2=+46\ \mu C`

Separation between spheres, d = 2.47 cm

We need to find the magnitude of the force that each sphere experiences. It is given by the formula as follows :

`F=k(q_1q_2)/(d^2)\\\\F=9* 10^9* (22* 10^(-6)* 46* 10^(-6))/((2.47* 10^(-2))^2) \\\\F=14928.94\ N\\\\F=1.49* 10^4\ N`

As the two charges have opposite sign, the force between them is attractive.