Question

Assume that room pressure is 97.3 kPa. Suppose you started with 15 mL of air in the syringe at room pressure. If the air is compressed to 3.0 mL, what will the new pressure be?

Answer 1

Step-by-step explanation:

room pressure p1 = 97.3 kPa

initial volume of air v1 = 15 mL

the air was compressed to a new volume of 3.0mL

using Boyle's law

p1v1 = p2v2

97300 × 15 mL = p2 × 3.0 mL

p2 = 1459500 / 3 = 486500 Pa = 486.5 KPa

Answer 2

Answer: the new pressure is 486.5 kpa

Step-by-step explanation:

We would apply Boyles law which states that the volume of a gas is inversely proportional to its pressure when the temperature of the gas is held constant.

It is expressed as

P1V1 = P2V2

Where

P1 represents initial pressure of the gas.

V1 = initial volume of the gas

P2 = final pressure of the gas

V2 = final volume of the gas

The gas is the air that is being compressed by the syringe. From the information given,

P1 = 97.3 kPa.

V1 = 15 mL

V2 = 3.0 mL

P2 = ?

Therefore,

97.3 × 15 = 3 × P2

1459.5 = 3P2

P2 = 1459.5/3

P2 = 486.5 kpa