Answer:
(d) 240/289
Explanation:
The trig identity for the sine of a double angle can be used to find the desired value.
sin(2θ) = 2sin(θ)cos(θ)
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The cosine of this 3rd-quadrant angle is negative:
cos(θ) = -√(1 -(-8/17)²) = -(√(289 -64))/17 = -15/17
Then the desired sine value is ...
sin(2θ) = 2(-8/17)(-15/17) = 240/289
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Additional comment
The attached calculator result comes from the principal value of the arcsine function resulting in a 4th-quadrant angle for negative sine values. Double that angle will still be a 4th-quadrant angle. When the translation is made to the appropriate quadrant, the desired double angle will be a 1st-quadrant angle with a positive sine.