Answer:
North of west
Step-by-step explanation:
Given
40,000-ton luxury line traveling 20 knots towards west and
60,000 ton freighter traveling towards North with 10 knots
suppose v is the common velocity after collision
conserving momentum in west direction
![20* 40,000=(20,000+60,000)v\cos \theta](https://img.qammunity.org/2021/formulas/physics/college/1y3xtc5ne1dcgpy10r2hwx55zf7jg6n8xx.png)
suppose the final velocity makes \theta angle with x axis
![v\cos \theta =10----1](https://img.qammunity.org/2021/formulas/physics/college/9gskga88wrivy1shjiimqgh4gsrfzf3gn9.png)
Conserving Momentum in North direction
![10* 60,000=80,000* v\sin\theta](https://img.qammunity.org/2021/formulas/physics/college/ooh5dhr87m5yq40u2mzrzhi13r2c41xvrv.png)
![v\sin \theta =(15)/(2)----2](https://img.qammunity.org/2021/formulas/physics/college/9de8bdgpld8c2r3mza7xjch9pb8zoqgyfu.png)
divide 1 and 2
![\tan \theta =(3)/(4)](https://img.qammunity.org/2021/formulas/physics/college/p99dy4hwttkaa3cxo049n8wrtt429g2wkv.png)
![\theta =37^(\circ)](https://img.qammunity.org/2021/formulas/physics/college/ejxxz0g88cl563zsyhx6k6vrawtopi7vzk.png)
so search in the area
North of west to find the ship