The pool can hold 65.84 ft³ of water
Step-by-step explanation:
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
![(11)/(1+√(2) ) = a^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gphsqosltrnlwf93kxzdwmptbra13ixxqa.png)
a² =
![(11)/(2.42)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/sf7k5s8ubw22qr5uzmkx1w8n5x6t0nblk4.png)
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon =
![2(1+√(2) ) X (a)^2 X h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/915nez3pdciny2ieajagp0oms73uhf7cb5.png)
![V = 2(1+√(2))X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fop1uxgib4scb18kxk08zj1hm9v3aosfm6.png)
Therefore, the pool can hold 65.84 ft³ of water