To determine whether the point is on the line, substitute/plug in either the x-value or the y-value of the point into the equation to see if it equals out:
3x - y = 4 I will use the x-value of the point, 2.
3(2) - y = 4
6 - y = 4 To find the value of "y", isolate/get the variable "y" by itself in the equation. Subtract 6 on both sides
6 - 6 - y = 4 - 6
-y = -2 Divide -1 on both sides to get "y" by itself
y = 2 -----> (2, 2)
No, this point is not on the line because when x is 2, y equals 2 not -2.