Question

When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 7.5 x10-7 m and a maximum speed of 3.3 x10-3 m/s. (a) What is the frequency (in Hz) of the eardrum's vibrations

Answer 1

f = 700 Hz

Step-by-step explanation:

given

amplitude =
`a= 7.5 * 10^(-7) m`

speed v =
`3.3 * 10^(-3)` m/s

for (a)

we know
`v_(max) = a\omega`

and
`\omega = 2\pi f`

we get

`v_(max) = a( 2 \pi f)`

`f = (v_(max))/(2 \pi a)`

`f = ( 3.3 * 10^(-3))/( 2 * 3.14 * 7.5 * 10^(-7))`

`f = 700 Hz`