42.9k views
0 votes
What is the surface area of a cylinder with base radius 3 and height 8?

User Small
by
8.7k points

1 Answer

5 votes

Final answer:

The surface area of a cylinder with a base radius of 3 and a height of 8 is approximately 210 square units, after rounding to two significant figures.

Step-by-step explanation:

The surface area of a cylinder is calculated by adding the areas of the two circular bases to the area of the rectangle that wraps around the cylinder when it is 'unrolled'. For a cylinder with a base radius of 3 and a height of 8, the formula for the total surface area (SA) is:

SA = 2πr2 + 2πrh

Where π is approximately 3.1416, r is the radius of the cylinder, and h is the height. Inputting our values, we get:

SA = 2π(32) + 2π(3)(8) = 2π(9) + 2π(24) = 18π + 48π = 66π

So the surface area SA is: 66 × 3.1416 ≈ 207.346 square units. However, since our values were given with only one decimal or significant figure, we should appropriately round our answer to two significant figures:

SA ≈ 210 square units

User Takanori
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories