Question

Ethanol is produced industrially by the reaction of ethylene with water in the presence of an acid catalyst. How many grams of ethanol are produced from 5.40 mol of ethylene? Assume that excess water is present.

Answer 1

Answer: 249 grams

Step-by-step explanation:

The balanced chemical equation is :

`C_2H_4+H_2O\rightarrow C_2H_5OH`

As water is present in excess , it is called as excess reagent and ethylene is the limiting reagent.

According to stoichiometry:

1 mole of ethylene produces = 1 mole of ethanol

Thus 5.40 mole of ethylene produces =
`(1)/(1)* 5.40=5.40` mole of ethanol

Mass of ethanol =
`moles* {\text {molar mass}}=5.40mol* 46.07g/mol=249g`

Thus 249 g of ethanol are produced from 5.40 mol of ethylene