Question

You fill a balloon with helium gas to a volume of 2.68L at 23°C and 789mmHg. Then you release the balloon and it rises. What will the volume be when the pressure drops to 632mm Hg if the temperature remains the same?

Answer 1

Answer : The final volume of balloon will be, 3.35 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

`P\propto (1)/(V)`

or,

`P_1V_1=P_2V_2`

where,

`P_1` = initial pressure = 789 mmHg

`P_2` = final pressure = 632 mmHg

`V_1` = initial volume = 2.68 L

`V_2` = final volume = ?

Now put all the given values in the above equation, we get:

`789mmHg* 2.68L=632mmHg* V_2`

`V_2=3.35L`

Therefore, the final volume of balloon will be, 3.35 L