Question

Sylvia and Jadon now want to work a problem. Imagine a puck of mass 0.5 kg moving as in the simulation. Suppose that the tension in the string is 3.0 N, and that the radius of its circular path is 0.6 m. What will Jadon and Sylvia find for the tangential speed of the puck?

Answer 1

1.897 m/s

Step-by-step explanation:

The tension T = 3N of the string is caused by the centripetal acceleration of the puck, which can be calculated as the following using Newton's 2nd law:

`a_c = T / m = 3 / 0.5 = 6 m/s^2`

From the centripetal acceleration, the tangential speed of the puck can be calculated using the following formula

`a_c = v^2/r`

`v^2 = a_c r = 6*0.6 = 3.6`

`v = √(3.6) = 1.897 m/s`