Answer:
![V=169.56\ mm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/9y9pfeia60mz6tgaiiqtaicnkz02puubnr.png)
Explanation:
we know that
The volume of the cone is given by te formula
![V=(1)/(3)\pi r^(2)h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1dtpmkchi8pftqr09lg7s0bchcrh5xhb6y.png)
we have
![V=113.04\ mm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/9fqm2j8odmu9j68wqpo18a4qv2c83snxzu.png)
substitute
![113.04=(1)/(3)\pi r^(2)h](https://img.qammunity.org/2021/formulas/mathematics/high-school/wnskjymdtyptguj0afpymg1vb6qwg09ot6.png)
----> equation A
Remember that
A sphere has the same height and a circular base with the same diameter
That means----> The diameter of the sphere is equal to the height of the cone and the radius of the sphere is equal to the radius of the base of cone
![r=(h)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/ax18beq5b94yy0smkkpy25rnpxxobdfzso.png)
equation A is equal to
![339.12=\pi ((h)/(2))^(2)h](https://img.qammunity.org/2021/formulas/mathematics/high-school/667crqyyoms84e0qo5fxqfb4zwc6bxh2vo.png)
![339.12=\pi ((h^3)/(3))](https://img.qammunity.org/2021/formulas/mathematics/high-school/h3u61ev3z7fniy6uykscpfvfuxwsfq9dss.png)
-----> equation B
The volume of the sphere is given by
![V=(4)/(3)\pi r^(3)](https://img.qammunity.org/2021/formulas/mathematics/college/65mo1js0p3q1eic79g8pf6918so5ij56y2.png)
substitute
![V=(4)/(3)\pi ((h)/(2))^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/szc1tt34mt967rvdiy6qtcofz7zxugqbuh.png)
![V=(4)/(24)\pi h^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/7127k0nopii2mp3jwa43eivicuo9s4x7gd.png)
![V=(1)/(6)\pi h^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/6qwwvxlejbyjqmms0xoe5bhk6zz1m5e8c0.png)
substitute equation B in the expression above
![V=(1)/(6)(1,017.36)=169.56\ mm^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/vni25aoarxqwq1i9wggfh8ilkje77na314.png)