Question

A wire carries a current of 0.76 A. This wire makes an angle of 46° with respect to a magnetic field of magnitude 6.0 × 10-5 T. The wire experiences a magnetic force of magnitude 9.4 × 10-5 N. What is the length of the wire?

Answer 1

The length of the wire is 2.86 m

Step-by-step explanation:

Given:

Current
`I = 0.76` A

Magnetic field
`B = 6 * 10^(-5)` T

Force
`F = 9.4 * 10^(-5)` N

Angle between wire and magnetic field
`\theta =` 46°

The magnetic force on the current carrying wire is given by,

`F = BIl\sin \theta`

Where
`l =` length of wire

`l = (F)/(BI \sin 46)`

`l = (9.4 * 10^(-5) )/(6 * 10^(-5)* 0.76 * 0.7193)`

`l = 2.86` m

Therefore, the length of the wire is 2.86 m