Question

For the geometric sequence where a1 = 3 and r = √2 find the 10th term of the sequence

Answer 1

48 square root 2

Explanation:

Answer 2

`48 √(2)`

Explanation:

nth term of a Geometric sequence is given as:

`t_n = ar^(n-1) \\ \therefore \: t_(10) = 3 * (√(2)) ^(10-1) \\ \therefore \: t_(10) = 3 * (√(2)) ^(9) \\ \therefore \: t_(10) = 3 * (√(2)) ^(8) * √(2)\\ \therefore \: t_(10) = 3 * ({2}) ^(4) * √(2)\\ \therefore \: t_(10) = 3 * 16 * √(2) \\ \huge \red { \boxed{\therefore \: t_(10) = 48 √(2) }}`

Hence, tenth term is
`48 √(2)`