Question

What are the coordinates of the vertex of the function f(x)=x^2+10x-3

Answer 1

(-5,-28)

Explanation:

f(x)=x^2+10x-3

Axis of symmetry is -b/2a.

-10/2 = -5. This is the x value of the vertex.

Plug in to solve for y.

-5^2+10(-5)-3 = -28.