Question

Temperature reaches

2. A sample of nitrogen gas has a pressure of 6.54 kPa at 537 K. If the volume
does not change, what will be the pressure at 179 K?

Answer 1

The pressure at 179 K is 21.8 kiloPascal.

Step-by-step explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

`(P_1)/(T_1)=(P_2)/(T_2)`

where,

`P_1\text{ and }T_1` are the initial pressure and temperature of the nitrogen gas.

`P_2\text{ and }T_2` are the final pressure and temperature of the nitrogen gas.

We are given:

`P_1=6.54 kPa\\T_1=537 K\\P_2=?\\T_2=179 K`

Putting values in above equation, we get:

`(6.54 kPa)/(537 K)=(P_2)/(179 K)\\\\P_2=2.18 kPa`

The pressure at 179 K is 21.8 kiloPascal.