Question

2 points

4) A spherical weather balloon has volume of 12.0 L when inflated at STP.
Assuming it could stay anchored and intact, as a hurricane passed
overhead lowering the pressure to 720.0 mm Hg what would be the new
volume of the balloon assuming the temperature stays at 0 C?
0 0.0167L
O 12.7L
0 0.0167 atm
O 11.36

Answer 1

(b) 12.7 L

Step-by-step explanation:

Given:

Volume, V₁ = 12 L

Pressure, P₁ = 760 mm Hg (at STP)

Temperature, T₁ = 273 K (at STP)

Pressure, P₂ = 720 mm Hg

Temperature, T₂ = 0°C = 273 K

Volume, V₂ = ?

We know:

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)`

Substituting the value we get:

`(760 X 12)/(273) = (720 X V_2)/(273) \\\\V_2 = (760 X 12)/(720) \\\\V_2 = 12.7 L`

Therefore, V₂ is 12.7 L