Question

4.00 L of a gas is known to contain 0.975 mol. If the amount of gas is increased to 3.80 mol, what new volume will result?

Answer 1

The new volume is 15.59L

Step-by-step explanation:

Given:

Initial volume, V₁ = 4L

Initial number of moles, n₁ = 0.975 mol

Final number of moles, n₂ = 3.8 mol

New volume, V₂ = ?

According to Avogadro's law:

`(V_1)/(n_1) = (V_2)/(n_2)`

Substituting the values we get:

`(4)/(0.975) = (V_2)/(3.8) \\\\V_2 = (3.8 X 4)/(0.975) \\\\V_2 = 15.59 L`

Therefore, the new volume is 15.59L