Answer: a. 7.31 g
b. 20.4 %
Step-by-step explanation:
To calculate the moles :


According to stoichiometry :
3 moles of
require = 1 mole of

Thus 0.645 moles of
will require=
of

Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 3 moles of
give = 2 moles of

Thus 0.645 moles of
give =
of

Mass of

Thus theoretical yield for this reaction under the given conditions is 7.31 g.
b)


The percent yield for this reaction under the given conditions is 20.4 %