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Susan tossed a die 828 ximes. Which of the following would be a good

estimate of the number of times she got the number 3 on the die?
A.283
B.93
C.240
D. 151

User Biaobiaoqi
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1 Answer

3 votes

Answer:

E(x)=138

Explanation:

let x be the number of times a '3' shows up from a toss.

-Assuming, Susan tosses a fair the die, with 6 sides, each side has an equal probability of showing up:


P(s)=P(1)=P(2)....=P(5)=P(6)=(1)/(6)

Given that the coin is tossed 828 times, the expected value of x is calculated as:


E(x)=np\\\\=828* (1)/(6)\\\\=138

Hence, the expected value of 3 in 828 tosses is 138

*Answer not in options provided.

User Thibaultcha
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