Answer:
x=11
6 is extraneous
Explanation:
sqrt( x-2) +8=x
Subtract 8 from each side
sqrt( x-2) +8-8=x-8
sqrt(x-2) = x-8
Square each side
(sqrt(x-2))^2 = (x-8)^2
x-2 = (x-8) (x-8)
x-2 = x^2 - 8x -8x +64
x-2 = x^2 - 16x +64
Subtract x from each side
x-x-2 = x^2 - 16x -x +64
-2 = x^2 - 17x +64
Add 2 to each side
-2+2 =x^2 - 17x +64+2
0 = x^2 - 17x +66
Factor
0 = (x- 11) (x-6)
Using the zero product property
x-11=0 x-6 =0
x=11 x=6
Check the solutions
x=11
sqrt( 11-2) +8=11
sqrt(9) +8 =11
3+8 =11 true
x=6
sqrt( 6-2) +8=6
sqrt(4) +8 =6
2 +8 = 6 false