Given:
Height of small rectangle = 6
Width of small rectangle = 2
Height of large rectangle = x
Width of large rectangle = 4
To find:
The missing side x.
Solution:
The corresponding sides of triangles are in the same ratio.
![$\frac{\text{ One side of large rectangle}}{\text{Corresponding side of small rectangle}}= \frac{\text{Other side of large rectangle}}{\text{Corresponding side of small rectangle}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/ropymmnxk8youhf49rc42ptpqgrv8awr16.png)
![$\Rightarrow (x)/(6) =(4)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vv6js67e6spdfkdsqtdb2fmw0e9vry8ri7.png)
Multiply by 6 on both sides.
![$\Rightarrow (x)/(6) * 6=(4)/(2)* 6](https://img.qammunity.org/2021/formulas/mathematics/high-school/3ppg03ns1649onix9fz4ftib8c4gzznr4n.png)
![$\Rightarrow x=2 * 6](https://img.qammunity.org/2021/formulas/mathematics/high-school/5wa6wfjr8hynvxucu8kpvn68vrse56du0x.png)
![$\Rightarrow x=12](https://img.qammunity.org/2021/formulas/mathematics/high-school/57mh3kkfr7qqw8bktqtf5965vphapos7ze.png)
The missing side is 12.