Question

After soccer practice coach Miller goes to the roof of the school to retrieve the event soccer balls the height of the school is 3.5 m a soccer ball which leaves the roof with only a horizontal velocity of 15 m/s in the ignoring air resistance how far is the ball above the ground at 0.32 seconds

Answer 1

50.2 cm

Step-by-step explanation:

We are given that

Height ,h=3.5 m

Initial horizontal velocity,
`u_x=15 m/s`

Time,t=0.32 s

We have to find the distance of ball from the ground at 0.32 s.

Initial vertical velocity,
`u_y=0`

`s=u_yt+(1)/(2)gt^2`

Where
`g=9.8 m/s^`

`s=0+(1)/(2)(9.8)(0.32)^2`

`s=0.502 m`

`s=0.502* 100=50.2 cm`