Question

A battery charger used to recharge the NiMH batteries used in a digital camera can deliver as much as 0.35 A of current. If it takes 145 minutes to recharge one battery, how many g Ni(OH)2 are oxidized to NiO(OH)

Answer 1

The amount that oxidized to NiO(OH) is = 1.46 gm

Step-by-step explanation:

Given data

Current I = 0.35 A

Time taken = 145 min

We know that charge

Q = I t

Q = 0.35 × 145 × 60

Q = 3045 C

Faraday's constant = 96500 C

No. of moles of electron

`N = (3045)/(96500)`

N = 0.03155

1 mol of
`NI(OH)_(2)` is oxidized by 2 moles of electrons, so no. of moles can be oxidized is

`(0.03155)/(2)` = 0.015775 moles

Now convert this moles into gm by multiplying 92.708
`(gm)/(mol)`

0.015775 × 92.708 = 1.46 gm

Therefore the amount that oxidized to NiO(OH) is = 1.46 gm