Question

A soccer player kicks a ball, changing its momentum by 11 kg. M/s, The net force on the ball is 910 N. How long does the soccer player maintain contact with the ball?

Answer 1

Answer: 0.012

Explanation: got it from khan

Answer 2

Contact maintained by the soccer player, with the ball is of 0.01 seconds.

Step-by-step explanation:

Given:

Change in momentum of the ball, Δp =
`11\ kg.m.s^-1`

Net applied force on the ball, F =
`910\ N`

We have to find for how long the soccer player maintains contact with the ball.

Formula to be used:

Acceleration = Ratio of change in velocity and time.

⇒
`a=(\triangle v)/(\triangle t)`

⇒
`\triangle v=a \triangle t`

Momentum = Product of mass of an object and applied time.

⇒
`\triangle p=m \triangle v`

⇒
`\triangle p=ma \triangle t` ..plugging
`\triangle v=a \triangle t`

⇒
`\triangle p=F \triangle t` ..Newtons seconds law,
`F=ma`

⇒
`\triangle t=(\triangle p)/(F)` ..re-arranging the equation.

Plugging the value of force and momentum we have.

⇒
`\triangle t=(\triangle p)/(F)`

⇒
`\triangle t=(11)/(910)`

⇒
`\triangle t =0.01` sec

So,

The soccer player maintain contact with the ball for 0.01 seconds.