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How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237 g?

User Taffit
by
7.8k points

2 Answers

5 votes

Answer:

3.68•10^21 particles (correct to 3SF)

Step-by-step explanation:

1.45 • xg molecular compound • 1mol/237g • (6.02•10^23)/ 1 mol = 3.6831•10^21 representative particles

*6.02•10^23 is Avagadro's number

User Simon Zyx
by
7.7k points
6 votes

Answer:

3.683×10^21 particles

Step-by-step explanation:

Number of particles in a substance = (mass of the substance/molar mass of the substance)×Avogadro's number

Given;

Mass of compound =1.45g

Molar mass of compound =237g

Avogadro's number=6.02×10^23

Therefore, number of particles = (1.45/237)×6.02×10^23

=3.683×10^21 particles

User Kainlite
by
7.7k points