Question

A container has a total pressure of 1439 mmHg. There are 3 gases in this container, one has a pressure of 523.3 mm Hg, and another has a pressure of 509.8 mm Hg. What is the pressure of the 3rd gas?

Answer 1

P₃ = 594.1 mmHg

Step-by-step explanation:

Given data:

Total pressure of container = 1439 mmHg

Partial pressure of 1st gas = 523.3 mmHg

Partial pressure of 2nd gas = 509.8 mmHg

Partial pressure of 3rd gas = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this problem by using this law.

P(total) = P₁ + P₂ + P₃

439 mmHg = 523.3 mmHg + 509.8 mmHg + P₃

439 mmHg = 1033.1 mmHg + P₃

P₃ = 1033.1 mmHg -439 mmHg

P₃ = 594.1 mmHg