Question

With process Plz！！Thank you very much

Answer 1

Explanation:

In circle with centre O.

`OA \cong OB.. (Radii\: of \:same \:circle) \\</p><p>\therefore m\angle OAB = m\angle OBA =28°\\</p><p>(m \angle 's \:opposite \:to \:congruent \:sides \:\\are \:equal)`

`m \angle AOB = 180°-(m\angle OAB + m\angle OBA)\\</p><p>\therefore\: m \angle AOB = 180°-(28° + 28°)\\</p><p>\therefore\: m \angle AOB = 180°-56°\\</p><p>\therefore\: m \angle AOB = 124°\\</p><p>m \angle ACB = (1)/(2) * m \angle AOB`

`(m\angle\: formed\: on\: the \:circle \:\\is\: half\: the\:\angle\: formed\: at\: the \:center\: \\of \:the \:circle)`

`\therefore\: m \angle ACB = (1)/(2) * 124°\\</p><p>\therefore\: m \angle ACB = 62°\\`