Question

8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?

Answer 1

1000 N

Step-by-step explanation:

The magnitude of the electrostatic force between two charged object is given by

`F=k(q_1 q_2)/(r^2)`

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

`q_1=q_2=+1C` are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

`F=(9\cdot 10^9)((1)(1))/(3000^2)=1000 N`