Final answer:
The volume of 4.9 mol of an ideal gas at a pressure of 3 atm and a temperature of 0°C is 109.64 L.
Step-by-step explanation:
To find the volume of 4.9 mol of an ideal gas at a pressure of 3 atm and a temperature of 0°C, we can use the ideal gas law equation: PV = nRT. Here, P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.08206 L-atm/mol-K), and T is the temperature in Kelvin. To convert the temperature from Celsius to Kelvin, we add 273.15. Plugging in the given values: V = (4.9 mol)(0.08206 L-atm/mol-K)(273.15 K)/(3 atm) = 109.64 L. Therefore, the volume of 4.9 mol of the ideal gas is 109.64 L.