Question

HELLPPPPPPPPPPPP!!!!!!!!!!!!! I NEED HELP I GOT 1 MIN OR LESS

Find the surface area of a square pyramid with base edges of 8 feet. The height of each lateral face is 15 feet. Explain or show how you got your answer.

Answer 1

`\sf\large\underline{\star Given:-}`

`\rightarrow` Measure of its each edge =
`\sf\red{8feet.}`

`\rightarrow` Height of each lateral surface (or slant height) =
`\sf\red{15feet.}`

`\sf\large\underline{\star To\: Find:-}`

• Surface area of the given square pyramid.

`\sf\large\underline{\star Formula \:Used:-}`

`\rightarrow` Surface Area of square pyramid =
`\sf\blue{a^2+2al}`

Where,

`\sf\pink{a^2}`
`\sf{=\: Area \: of\: base.}`

`\sf\pink{a}`
`\sf{=\: Side \:of \:the\: base.}`

`\sf\pink{l}`
`\sf{=\: Slant \:height}`

`\sf\large\underline{\star Solution:-}`

`\rightarrow` Surface Area of square pyramid =
`\sf{a^2+2al}`(putting the value of
`\sf{a^2}`, a and l)

`\rightarrow`
`\sf{=\: 8^2+2(8×15)}`

`\rightarrow`
`\sf{=\: 304feet^2}`

Therefore, surface area of the given square pyramid
`\sf\purple{=\: 304feet^2.}`

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Hope it helps you:)