Answer:
2250 N
Step-by-step explanation:
Assuming the driver decelerates at the same rate as the car:
a = (0 m/s − 5 m/s) / (0.20 s)
a = -25 m/s²
F = ma
F = (90 kg) (-25 m/s²)
F = -2250 N
The magnitude of the average force on the driver is 2250 N.
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