A teacher can make 35 quizzes.
Explanation:
Given that,
Total problems = n = 7
Number of questions in a quiz = r = 4
We need to find the ways in which different 4-question geometry quizzes can a teacher make if there are 7 different problems to test.
For that, the combination is used: nCr =
![(n!)/(r!(n-r)!)](https://img.qammunity.org/2021/formulas/mathematics/high-school/frlstu9is48umu8jpn9qy7mlq5z57a89s6.png)
By putting the values, we get
![(7!)/(4!(7-4)!)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wby4joc0oq4xljbbz2vxfu9kpgl5b0v4rx.png)
![(7*6*5*4!)/(4!*3!)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vnkjtp8itdcojvrknmmtp26p2f2qg3tqzy.png)
![(7*6*5)/(3*2*1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7gs99659gj1brotad4737hjioqq3n95dvc.png)
35 quizzes
Hence, a teacher can make 35 quizzes.