PLS HELP In circle A, secant EC and tangent BC intersect at point C. mЕВ = 171° and mBD 83°. What is mBCD? Enter your answer in the box.

Mirap asked Jun 13, 2023

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PLS HELP In circle A, secant EC and tangent BC intersect at point C. mЕВ = 171° and mBD 83°. What is mBCD?

Enter your answer in the box.

Mirap asked Jun 13, 2023

by Mirap

2.6k points

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19 votes

Answer:

∠ BCD = 44°

Explanation:

the secant- tangent angle BCD is half the difference of the intercepted arcs, so

∠ BCD =
(1)/(2) (EB - BD) =
(1)/(2) (171 - 83)° =
(1)/(2) × 88° = 44°

Sachin Chavan answered Jun 18, 2023

3.1k points

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