Question

If 112 g fr combines with 48 g of O2 how much fe2O3 is formed

Answer 1

160 g.

Step-by-step explanation:

The balanced equation is

4Fe + 3O2 ---> 2Fe2O3.

4 * 56 g of Fe reacts with 6 * 16 g of O2 to give 2 * 160 g Fe2O3.

224 g Fe reacts with 96g of O2 to give 320 g Fe2O3.

So 48 g O2 + 224 g Fe produces 320 * 1/2 = 160 g Fe2O3.